Question:- Express (1,2,3) as a linear combination of
(1,1,1),(2,-1,1) and (1,-2,5) in V3(R).
Solution:-Let a1,a2,a3∊R
such that
(1,2,3)=(a1,a1,a1)+(2a2,-a2,a2)+(a3,-2a3,5a3)
(1,2,3)=(a1+2a2+a3,
a1-a2-2a3, a1+a2+5a3)
⇨ a1+2a2+a3=1
……………………………(1)
a1+a2+a3=2 ……………………………..(2)
and a1+a2+5a3=3……………………………..(3)
Substracting equa(3) from
(1)
We get 3a2+3a3=-1……………………………….(4)
Again, substracting equa(3)
from (2)
We get -2a2-7a3=-1
or 2a2+7a3=1………………………………..(5)
Now, multiplying by 2 in
(4) & 3 in (5) and then substracting
(5) from (4)
We get 15a3=5
⇨ a3=1/3
Putting ‘a3’ in (4)
We get
3a2+3
=-1
⇨ a2=-2/3
Putting a2 & a3 in equa(2)
We get
a1=2-
-
⇨ a1=2
Since from (a)
(1,2,3)=2(1,1,1)-2/3(2,-1,1)+1/3(1,-2,5)

No comments:
Post a Comment